4=1/32(2)^n-1

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Solution for 4=1/32(2)^n-1 equation: 



4=1/32(2)^n-1

We move all terms to the left:

4-(1/32(2)^n-1)=0



Domain of the equation: 322^n-1)!=0

n∈R



We get rid of parentheses

-1/322^n+1+4=0

We multiply all the terms by the denominator


1*322^n+4*322^n-1=0

Wy multiply elements

322n+1288n-1=0

We add all the numbers together, and all the variables

1610n-1=0

We move all terms containing n to the left, all other terms to the right

1610n=1

n=1/1610

n=1/1610

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